Creating combinations/permutations in python of a boolean list without using ITERTOOLS [closed]

Question

l = [True, True , False]

Without using itertools module.

How do yo create permutations of l in a new list

newlist = [[True,True,False],[True,True,True], [False,False,True],[False,False,False]....]

essentially this is what im trying to do:

allorderings = itertools.product ([False, True], repeat = n)

Answer 1

Use itertools.permutations

import itertools
l = [True, True , False]
newlist = list(itertools.permutations(l))

EDIT: from your question, one of the permutations you need is (True, True, True) which is not a permutation at all of the list l. This answer gives you permutations of a list in the technical sense and you may have to do extra work to achieve what you show in the question(unless of course that was a typo).

Answer 2

The simplest way I could think of, would be to iterate over the same list of items thrice and collect only the unique items, like this

l = set([True, True, False])
print {(i, j, k) for i in l for j in l for k in l}

Answer 3

Use itertools.permutations's equivalent in pure python from the official docs?