Creating an instance of a interface in c#

Question

I am using an interface in C# and rather than write an entirely new class which implements that interface is it possible to just create an object which implements that interface? The interface is defined as

public interface ITokenStore
{

    IToken CreateRequestToken(IOAuthContext context);


    IToken CreateAccessToken(IOAuthContext context);
}

And I know in java I could something like

ITokenStore tokenStore = new ITokenStore()
    {
        IToken CreateRequestToken(IOAuthContext context) {
            IToken requestToken = null;

            return requestToken;
        }

        IToken CreateAccessToken(IOAuthToken context) {
            IToken accessToken = null;

            return accessToken;
        }
    };

Is there an equivalent way to instantiate in instance of an interface in c#?

Answer 1

The only way to "Create an instance of a interface in c#" is to create an instance of a type implementing the interface.

Answer 2

Interfaces have no logic in them by design. They simply don't actually do anything.

Instantiating one without an implementing class doesn't even make sense