Try this:
Customer customerRecords[2] = {{25, "Bob Jones"},
{26, "Jim Smith"}};
You can't use an initialization-list for a struct
after it's been initialized. You've already default-initialized the two Customer
structs when you declared the array customerRecords
. Therefore you're going to have either use member-access syntax to set the value of the non-static data members, initialize the structs using a list of initialization lists when you declare the array itself, or you can create a constructor for your struct and use the default operator=
member function to initialize the array members.
So either of the following could work:
Customer customerRecords[2];
customerRecords[0].uid = 25;
customerRecords[0].name = "Bob Jones";
customerRecords[1].uid = 25;
customerRecords[1].namem = "Jim Smith";
Or if you defined a constructor for your struct like:
Customer::Customer(int id, string input_name): uid(id), name(input_name) {}
You could then do:
Customer customerRecords[2];
customerRecords[0] = Customer(25, "Bob Jones");
customerRecords[1] = Customer(26, "Jim Smith");
Or you could do the sequence of initialization lists that Tuomas used in his answer. The reason his initialization-list syntax works is because you're actually initializing the Customer
structs at the time of the declaration of the array, rather than allowing the structs to be default-initialized which takes place whenever you declare an aggregate data-structure like an array.
Some compilers support compound literals as an extention, allowing this construct:
Customer customerRecords[2];
customerRecords[0] = (Customer){25, "Bob Jones"};
customerRecords[1] = (Customer){26, "Jim Smith"};
But it's rather unportable.
It works perfectly. I have gcc compiler C++11 ready. Try this and you'll see:
#include <iostream>
using namespace std;
int main()
{
int pause;
struct Customer
{
int uid;
string name;
};
Customer customerRecords[2];
customerRecords[0] = {25, "Bob Jones"};
customerRecords[1] = {26, "Jim Smith"};
cout << customerRecords[0].uid << " " << customerRecords[0].name << endl;
cout << customerRecords[1].uid << " " << customerRecords[1].name << endl;
cin >> pause;
return 0;
}
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