I am searching for an elegant equivalent of this piece of code using Java 8's streams:
Collection<X> xs = ...;
Map<B, A> map = new SomeMap<>();
for (X x : xs) {
A a = x.getA();
Collection<B> bs = x.getBs();
for (B b : bs)
map.put(b, a);
}
That one is a bit too tricky for me as I can’t think of a combination using flatMap and Collectors.toMap which would implement the desired functionality.
Compilable example:
import java.util.Arrays;
import java.util.Collection;
import java.util.HashMap;
import java.util.Map;
public class Application {
public static class A {}
public static class B {}
public static class X {
private A a;
private Collection<B> bs;
public X(A a, Collection<B> bs) {
this.a = a;
this.bs = bs;
}
public A getA() {
return a;
}
public Collection<B> getBs() {
return bs;
}
}
public static void main(String[] args) {
X x1 = new X(new A(), Arrays.asList(new B(), new B()));
X x2 = new X(new A(), Arrays.asList(new B()));
Collection<X> xs = Arrays.asList(x1, x2);
Map<B, A> map = new HashMap<>();
for (X x : xs) {
A a = x.getA();
Collection<B> bs = x.getBs();
for (B b : bs)
map.put(b, a);
}
}
}
As you thought you can do it with a mixture of flatMap and toMap:
Map<B, A> map = xs.stream()
.flatMap(x -> x.getBs().stream()
.map(b -> new SimpleEntry<> (b, x.getA())))
.collect(toMap(Entry::getKey, Entry::getValue));
Note that this code differs from your original if there are duplicate Bs: your code will keep overwriting the corresponding value whereas this code will throw an exception.
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