Creating a Generic<T> type instance with a variable containing the Type

Question

Is it possible to achieve the following code? I know it doesn't work, but I'm wondering if there is a workaround?

Type k = typeof(double); List<k> lst = new List<k>(); 

Answer 1

Yes, there is:

var genericListType = typeof(List<>); var specificListType = genericListType.MakeGenericType(typeof(double)); var list = Activator.CreateInstance(specificListType); 

Answer 2

A cleaner way might be to use a generic method. Do something like this:

static void AddType<T>()     where T : DataObject {     Indexes.Add(typeof(T), new Dictionary<int, T>()); }