I'm trying to create a list equivalent for the very useful collections.defaultdict
. The following design works nicely:
class defaultlist(list):
def __init__(self, fx):
self._fx = fx
def __setitem__(self, index, value):
while len(self) <= index:
self.append(self._fx())
list.__setitem__(self, index, value)
Here's how you use it:
>>> dl = defaultlist(lambda:'A')
>>> dl[2]='B'
>>> dl[4]='C'
>>> dl
['A', 'A', 'B', 'A', 'C']
What should I add to the defaultlist so as to support the following behavior?
>>> dl = defaultlist(dict)
>>> dl[2]['a'] = 1
>>> dl
[{}, {}, {'a':1}]
On the example you give, you first try to retrieve a non-existing value on the list, as you do dl[2]['a']
, Python first retrieve the third (index 2) element on the list, then proceed to get the element named 'a' on that object - therefore you have to implement your automatic extending behavior to the __getitem__
method as well, like this:
class defaultlist(list):
def __init__(self, fx):
self._fx = fx
def _fill(self, index):
while len(self) <= index:
self.append(self._fx())
def __setitem__(self, index, value):
self._fill(index)
list.__setitem__(self, index, value)
def __getitem__(self, index):
self._fill(index)
return list.__getitem__(self, index)
There is a python package available:
$ pip install defaultlist
Added indicies are filled with None by default.
>>> from defaultlist import defaultlist
>>> l = defaultlist()
>>> l
[]
>>> l[2] = "C"
>>> l
[None, None, 'C']
>>> l[4]
>>> l
[None, None, 'C', None, None]
Slices and negative indicies are supported likewise
>>> l[1:4]
[None, 'C', None]
>>> l[-3]
'C'
Simple factory functions can be created via lambda.
>>> l = defaultlist(lambda: 'empty')
>>> l[2] = "C"
>>> l[4]
'empty'
>>> l
['empty', 'empty', 'C', 'empty', 'empty']
It is also possible to implement advanced factory functions:
>>> def inc():
... inc.counter += 1
... return inc.counter
>>> inc.counter = -1
>>> l = defaultlist(inc)
>>> l[2] = "C"
>>> l
[0, 1, 'C']
>>> l[4]
4
>>> l
[0, 1, 'C', 3, 4]
See the Documentation for any further details.
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