Creating a data frame from two vectors using cbind

Question

Consider the following R code.

> x = cbind(c(10, 20), c("[]", "[]"), c("[[1,2]]","[[1,3]]")) > x      [,1] [,2] [,3]      [1,] "10" "[]" "[[1,2]]" [2,] "20" "[]" "[[1,3]]" 

Similarly

> x = rbind(c(10, "[]", "[[1,2]]"), c(20, "[]", "[[1,3]]")) > x      [,1] [,2] [,3]      [1,] "10" "[]" "[[1,2]]" [2,] "20" "[]" "[[1,3]]" 

Now, I don't want the integers 10 and 20 to be converted to strings. How can I perform this operation without any such conversion? I would of course also like to know why this conversion happens. I looked at the cbind help and also tried Googling, but had no luck finding a solution. I also believe that in some cases. R converts strings to factors, and I don't want that to happen either, though it doesn't seem to be happening here.

Answer 1

Vectors and matrices can only be of a single type and cbind and rbind on vectors will give matrices. In these cases, the numeric values will be promoted to character values since that type will hold all the values.

(Note that in your rbind example, the promotion happens within the c call:

> c(10, "[]", "[[1,2]]") [1] "10"      "[]"      "[[1,2]]" 

If you want a rectangular structure where the columns can be different types, you want a data.frame. Any of the following should get you what you want:

> x = data.frame(v1=c(10, 20), v2=c("[]", "[]"), v3=c("[[1,2]]","[[1,3]]")) > x   v1 v2      v3 1 10 [] [[1,2]] 2 20 [] [[1,3]] > str(x) 'data.frame':   2 obs. of  3 variables:  $ v1: num  10 20  $ v2: Factor w/ 1 level "[]": 1 1  $ v3: Factor w/ 2 levels "[[1,2]]","[[1,3]]": 1 2 

or (using specifically the data.frame version of cbind)

> x = cbind.data.frame(c(10, 20), c("[]", "[]"), c("[[1,2]]","[[1,3]]")) > x   c(10, 20) c("[]", "[]") c("[[1,2]]", "[[1,3]]") 1        10            []                 [[1,2]] 2        20            []                 [[1,3]] > str(x) 'data.frame':   2 obs. of  3 variables:  $ c(10, 20)              : num  10 20  $ c("[]", "[]")          : Factor w/ 1 level "[]": 1 1  $ c("[[1,2]]", "[[1,3]]"): Factor w/ 2 levels "[[1,2]]","[[1,3]]": 1 2 

or (using cbind, but making the first a data.frame so that it combines as data.frames do):

> x = cbind(data.frame(c(10, 20)), c("[]", "[]"), c("[[1,2]]","[[1,3]]")) > x   c.10..20. c("[]", "[]") c("[[1,2]]", "[[1,3]]") 1        10            []                 [[1,2]] 2        20            []                 [[1,3]] > str(x) 'data.frame':   2 obs. of  3 variables:  $ c.10..20.              : num  10 20  $ c("[]", "[]")          : Factor w/ 1 level "[]": 1 1  $ c("[[1,2]]", "[[1,3]]"): Factor w/ 2 levels "[[1,2]]","[[1,3]]": 1 2