Create Multiple MySQL tables using PHP [closed]

Question

I am trying to create more then one MySQL tables using php but it gives errors and i can not sort out what is wrong with it.

PHP code :

$sql = ' CREATE TABLE IF NOT EXISTS `mod_reminder_entries` 
  ( 
   `id`          INT(10) NOT NULL auto_increment, 
   `user_id`     INT(10) NOT NULL, 
   `entry_name`  VARCHAR(255) NOT NULL, 
   `entry_value` INT(10) NOT NULL, 
   PRIMARY KEY (`id`), 
   FOREIGN KEY (`user_id`) REFERENCES tblclients (`id`) 
 ); 

 CREATE TABLE IF NOT EXISTS `second_table` 
  ( 
   `user_id`     INT(10) NOT NULL, 
   `fieldstotal` INT(10) NOT NULL, 
   FOREIGN KEY (`user_id`) REFERENCES tblclients (`id`) 
  ); ';

  mysql_query($sql);

It gives the error, besides do not worry about the mysql connection. I properly connect with the DB and i have tested it, it is definitely some thing wrong with syntax.

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE IF NOT EXISTS second_table ( user_id INT

Answer 1

You cannot use semicolon separated queries with mysql_query, this function only allows one query at a time!

You must execute your statements separately:

mysql_query("
    CREATE TABLE IF NOT EXISTS `mod_reminder_entries` (
        `id` INT(10) NOT NULL AUTO_INCREMENT, 
        `user_id` INT(10) NOT NULL, 
        `entry_name` VARCHAR(255) NOT NULL, 
        `entry_value` INT(10) NOT NULL, 
        PRIMARY KEY (`id`), 
        FOREIGN KEY (`user_id`) REFERENCES tblclients (`id`) 
    )
") or die(mysql_error());

mysql_query("
CREATE TABLE IF NOT EXISTS `second_table` (
    `user_id` INT(10) NOT NULL, 
    `fieldstotal` INT(10) NOT NULL, 
    FOREIGN KEY (`user_id`) REFERENCES tblclients (`id`) 
)
") or die(mysql_error());

Or better, use mysqli_multi_query -- which means you must switch to mysqli.