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gcc -o abc/def.o def.c generates def.o file in a directory abc; only when there exists a directory abc.
Is there a way to make gcc to create a directory when the enclosing directory of the generated object file does not exist? If not, what could be the easiest way to make the directory in advance automatically, especially for Makefile?
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You need to use the which command to locate c compiler binary called gcc. Usually, it is installed in /usr/bin directory.
Solution 1: build the directory when the Makefile is parsed Before any targets are created or commands run the Makefile is read and parsed. If you put $(shell mkdir -p $(OUT)) somewhere in the Makefile then GNU Make will run the mkdir every time the Makefile is loaded.
The fopen can't be used to create directories. This is because fopen function doesn't create or open folders, it only works with files. The above code creates a path to the file named 'filename'. The directory of the 'filename' is obtained using the 'dirname' function.
Linking is performed when the input file are object files " .o " (instead of source file " . cpp " or " . c "). GCC uses a separate linker program (called ld.exe ) to perform the linking.
From this post, it seems like that there is no way to create a directory from gcc.
For makefile, I can use this code snippet.
OBJDIR = obj
MODULES := src src2
...
OBJDIRS := $(patsubst %, $(OBJDIR)/%, $(MODULES))
build: $(OBJDIRS)
echo $^
$(OBJDIRS):
mkdir -p $@
make build will create directories, and echo the results.
We also can make the object files are created automatically without invoking the make build.
PROG := hellomake
LD := gcc
...
$(PROG): $(OBJDIRS) obj/src/hellofunc.o obj/src/hellomake.o
$(LD) $(filter %.o, $^) -o $(PROG)
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