I have worked in Python earlier where it is really smooth to have a dictionary of lists (i.e. one key corresponds to a list of stuff). I am struggling to achieve the same in vba. Say I have the following data in an excel sheet:
Flanged_connections 6
Flanged_connections 8
Flanged_connections 10
Instrument Pressure
Instrument Temperature
Instrument Bridle
Instrument Others
Piping 1
Piping 2
Piping 3
Now I want to read the data and store it in a dictionary where the keys are Flanged_connections
, Instrument
and Piping
and the values are the corresponding ones in the second column. I want the data to look like this:
'key' 'values':
'Flanged_connections' '[6 8 10]'
'Instrument' '["Pressure" "Temperature" "Bridle" "Others"]'
'Piping' '[1 2 3]'
and then being able to get the list by doing dict.Item("Piping")
with the list [1 2 3]
as the result. So I started thinking doing something like:
For Each row In inputRange.Rows
If Not equipmentDictionary.Exists(row.Cells(equipmentCol).Text) Then
equipmentDictionary.Add row.Cells(equipmentCol).Text, <INSERT NEW LIST>
Else
equipmentDictionary.Add row.Cells(equipmentCol).Text, <ADD TO EXISTING LIST>
End If
Next
This seems a bit tedious to do. Is there a better approach to this? I tried searching for using arrays in vba and it seems a bit different than java, c++ and python, with stuft like redim preserve
and the likes. Is this the only way to work with arrays in vba?
Based on @varocarbas' comment I have created a dictionary of collections. This is the easiest way for my mind to comprehend what's going on, though it might not be the most efficient. The other solutions would probably work as well (not tested by me). This is my suggested solution and it provides the correct output:
'/--------------------------------------\'
'| Sets up the dictionary for equipment |'
'\--------------------------------------/'
inputRowMin = 1
inputRowMax = 173
inputColMin = 1
inputColMax = 2
equipmentCol = 1
dimensionCol = 2
Set equipmentDictionary = CreateObject("Scripting.Dictionary")
Set inputSheet = Application.Sheets(inputSheetName)
Set inputRange = Range(Cells(inputRowMin, inputColMin), Cells(inputRowMax, inputColMax))
Set equipmentCollection = New Collection
For i = 1 To inputRange.Height
thisEquipment = inputRange(i, equipmentCol).Text
nextEquipment = inputRange(i + 1, equipmentCol).Text
thisDimension = inputRange(i, dimensionCol).Text
'The Strings are equal - add thisEquipment to collection and continue
If (StrComp(thisEquipment, nextEquipment, vbTextCompare) = 0) Then
equipmentCollection.Add thisDimension
'The Strings are not equal - add thisEquipment to collection and the collection to the dictionary
Else
equipmentCollection.Add thisDimension
equipmentDictionary.Add thisEquipment, equipmentCollection
Set equipmentCollection = New Collection
End If
Next
'Check input
Dim tmpCollection As Collection
For Each key In equipmentDictionary.Keys
Debug.Print "--------------" & key & "---------------"
Set tmpCollection = equipmentDictionary.Item(key)
For i = 1 To tmpCollection.Count
Debug.Print tmpCollection.Item(i)
Next
Next
Note that this solution assumes that all the equipment are sorted!
VBA does not have an internal implementation of a dictionary, but from VBA you can still use the dictionary object from MS Scripting Runtime Library.
Arrays in VBA are more or less like everywhere else with various peculiarities:
Sheets
array in a Workbook) are 1-based. Although, as rightly pointed out by @TimWilliams, the user-defined arrays are actually 0-based. The array below defines a string array with a length of 11 (10 indicates the upper position).Other than that and the peculiarities regarding notations, you shouldn't find any problem to deal with VBA arrays.
Dim stringArray(10) As String
stringArray(1) = "first val"
stringArray(2) = "second val"
'etc.
Regarding what you are requesting, you can create a dictionary in VBA and include a list on it (or the VBA equivalent: Collection
), here you have a sample code:
Set dict = CreateObject("Scripting.Dictionary")
Set coll = New Collection
coll.Add ("coll1")
coll.Add ("coll2")
coll.Add ("coll3")
If Not dict.Exists("dict1") Then
dict.Add "dict1", coll
End If
Dim curVal As String: curVal = dict("dict1")(3) '-> "coll3"
Set dict = Nothing
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