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Create combinations of numbers within list prolog

I am developing a program in PROLOG (with restrictions) which is supposed to output a combination of 6 numbers within certain restrictions.

The list must have the numbers from 1 to 4 and will, consequently, repeat 2 other numbers. It is not possible not to have a number from 1 to 4.

Possible examples:     Wrong examples:
1,2,3,4,1,1            1,2,3,2,3,3 //Missing #4
1,3,2,1,4,4            4,3,2,4,2,3 //Missing #1
1,2,3,3,2,4
4,1,3,2,1,4

In order to get this done I created some restrictions like the following:

Numbers = [A1, A2, A3, A4, A5, A6]
nCr(6,4) = 15 restrictions
A1 =\= A2 =\= A3 =\= A4 OR
A1 =\= A2 =\= A3 =\= A5 OR
Etc.

Here's the code I've developed so far:

make

pred(Numbers) :-

       Numbers = [A1, A2, A3, A4, A5, A6],
       domain(Numbers, 1, 4),

       %restrictions
       all_different([A1,A2,A6,A3]) #\/    %A1 =/= A2 =/= A6 =/= A3
        all_different([A1,A2,A6,A4]) #\/    %A1 =/= A2 =/= A6 =/= A4
         all_different([A1,A2,A6,A5]) #\/    %A1 =/= A2 =/= A6 =/= A5
          all_different([A1,A2,A3,A4]) #\/    %A1 =/= A2 =/= A3 =/= A4
           all_different([A1,A2,A3,A5]) #\/    %A1 =/= A2 =/= A3 =/= A5
            all_different([A1,A2,A4,A5]) #\/    %A1 =/= A2 =/= A4 =/= A5
             all_different([A1,A6,A3,A4]) #\/    %A1 =/= A6 =/= A3 =/= A4
              all_different([A1,A6,A3,A5]) #\/    %A1 =/= A6 =/= A3 =/= A5
               all_different([A1,A6,A4,A5]) #\/    %A1 =/= A6 =/= A4 =/= A5
                all_different([A1,A3,A5,A4]) #\/    %A1 =/= A3 =/= A4 =/= A5
                 all_different([A2,A6,A3,A4]) #\/    %A2 =/= A6 =/= A3 =/= A4
                  all_different([A2,A6,A3,A5]) #\/    %A2 =/= A6 =/= A3 =/= A5 
                   all_different([A2,A6,A4,A5]) #\/    %A2 =/= A6 =/= A4 =/= A5
                    all_different([A2,A3,A4,A5]) #\/    %A2 =/= A3 =/= A4 =/= A5 
                     all_different([A6,A3,A4,A5]),    %A6 =/= A3 =/= A4 =/= A5

           labeling([], Numbers).

The logic seems fine to me, but this implementation is not working as it should. There are no solutions which meet the restrictions typed. Can anyone give me a hand?

| ?- pred([A1, A2, A3, A4, A5, A6]).
no
like image 923
GRoutar Avatar asked Dec 12 '14 18:12

GRoutar


2 Answers

this query should satisfy your requirements

?- Vs = [_,_,_,_,_,_], Vs ins 1..4,
   [A,B,C,D] ins 1..2, global_cardinality(Vs, [1-A,2-B,3-C,4-D]), label(Vs).
Vs = [1, 1, 2, 2, 3, 4],
A = B, B = 2,
C = D, D = 1 ;
Vs = [1, 1, 2, 2, 4, 3],
A = B, B = 2,
C = D, D = 1 ;
...
like image 50
CapelliC Avatar answered Sep 26 '22 10:09

CapelliC


Here are two alternative queries using clpfd constraints:

  1. Using the nvalue/2 constraint, available with SICStus Prolog:

    ?- Vs = [_,_,_,_,_,_], domain(Vs,1,4),
       nvalue(4,Vs),
       labeling([],Vs).
    
  2. Using the element/3 constraint, the clpfd sibling of nth1/3 and member/2:

    ?- Vs = [_,_,_,_,_,_], domain(Vs,1,4),
       element(_,Vs,1),element(_,Vs,2),element(_,Vs,3),element(_,Vs,4),
       labeling([],Vs).
    

Both queries give the same solution sequence:

Vs = [1,1,1,2,3,4] ? ;
Vs = [1,1,1,2,4,3] ? ;
Vs = [1,1,1,3,2,4] ? ;
Vs = [1,1,1,3,4,2] ? ;
Vs = [1,1,1,4,2,3] ? ;
Vs = [1,1,1,4,3,2] ? ...

The list above only includes the first few results, there are 1560 in total.

like image 23
repeat Avatar answered Sep 26 '22 10:09

repeat