Create a object i an object based on the array of string value

Question

I need to update the object name based on the array of the string value and the last string value should be an array.

I use array.forEach loop but I don't know how to find the object inside an object if it exists and the myArray contain around 10,000 strings.

const myArray = [
  '/unit/unit/225/unit-225.pdf',
  '/nit/nit-dep/4.11/nit-4.11.pdf',
  '/nit/nit-dep/4.12/nit-4.12.pdf',
  '/org/viti/viti-engine/5.1/viti-engine-5.1.pdf',
  '/org/viti/viti-spring/5.1/viti-spring-5.1.pdf'
];
var parentObject = {}
myArray.forEach(res => {
  res = res.slice(1, res.length);
  var array = res.split("/");
  array.forEach((e, i) => {
    ........ // here I am confused 

  });
})

final output should be

parentObject = {
  'unit': {
    'unit': {
      '225': {
        'unit-225.pdf': []
      }
    }
  },
  'nit': {
    'nit-dep': {
      '4.11': {
        'nit-4.11.pdf': []
      },
      '4.12': {
        'nit-4.12.pdf': []
      }
    }
  },
  'org': {
    'viti': {
      'viti-engine': {
        '5.1': {
          'viti-engine-5.1.pdf': []
        }
      },
      'viti-spring': {
        '5.2': {
          'viti-engine-5.2.pdf': []
        }
      }
    }
  }
}

Answer 1

Once you've split by slashes, use reduce to iterate to the nested object, creating each nested property first if necessary, then assign an array to the filename property:

const myArray = [
  '/unit/unit/225/unit-225.pdf',
  '/nit/nit-dep/4.11/nit-4.11.pdf',
  '/nit/nit-dep/4.12/nit-4.12.pdf',
  '/org/viti/viti-engine/5.1/viti-engine-5.1.pdf',
  '/org/viti/viti-spring/5.1/viti-spring-5.1.pdf'
];
var parentObject = {}
myArray.forEach((str) => {
  const props = str.slice(1).split('/');
  const filename = props.pop();
  const lastObj = props.reduce((a, prop) => {
    if (!a[prop]) {
      a[prop] = {};
    }
    return a[prop];
  }, parentObject);
  lastObj[filename] = [];
});
console.log(parentObject);

Answer 2

You could reduce the array an reduce the path as well. At the end assign the array.

const
    array = ['/unit/unit/225/unit-225.pdf', '/nit/nit-dep/4.11/nit-4.11.pdf', '/nit/nit-dep/4.12/nit-4.12.pdf', '/org/viti/viti-engine/5.1/viti-engine-5.1.pdf', '/org/viti/viti-spring/5.1/viti-spring-5.1.pdf'],
    result = array.reduce((r, path) => {
        var keys = path.split(/\//).slice(1),
            last = keys.pop();

        keys.reduce((o, k) => o[k] = o[k] || {}, r)[last] = [];
        return r;
    }, {});

console.log(result);

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A slightly faster approach.

const
    array = ['/unit/unit/225/unit-225.pdf', '/nit/nit-dep/4.11/nit-4.11.pdf', '/nit/nit-dep/4.12/nit-4.12.pdf', '/org/viti/viti-engine/5.1/viti-engine-5.1.pdf', '/org/viti/viti-spring/5.1/viti-spring-5.1.pdf'],
    result = {};

for (let path of array) {
    let keys = path.split(/\//).slice(1),
        last = keys.pop(),
        temp = result;

    for (let key of keys) {
        temp[key] = temp[key] || {};
        temp = temp[key];
    }
    temp[last] = [];
}

console.log(result);

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