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I was wondering if it's possible to make a pointer not a pointer..
The problem is I have a function that accepts a pointer for an paramater for me to easily get a value to that pointer. It's a simple int so I was wondering if I could just get that value without needing to send around a pointer wherever I want the value to land.
I don't want the function to return the value as an int as it's giving a value to 2 pointers!
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To get the value pointed to by a pointer, you need to use the dereferencing operator * (e.g., if pNumber is a int pointer, *pNumber returns the value pointed to by pNumber . It is called dereferencing or indirection).
From the memory-allocation point-of-view, you're right. A pointer variable on a 64-bit architecture occupies 8 bytes, no matter what type of pointer it is. But the C compiler needs to know more about a variable than its size.
The fundamental rules of pointer operators are: The * operator turns a value of type pointer to T into a variable of type T . The & operator turns a variable of type T into a value of type pointer to T .
To get the value of a pointer, just de-reference the pointer.
int *ptr; int value; *ptr = 9; value = *ptr; value is now 9.
I suggest you read more about pointers, this is their base functionality.
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