Counting vowels in an array

Question

I know I'm close to figuring this out but I've been wracking my brain and can't think of what's going wrong here. I need to count the number of vowels in the array of nameList using the vowelList array, and currently it's outputting 22, which is not the correct number of vowels.

Incidentally, 22 is double the length of the array nameList, but I can't see any reason what I wrote would be outputting double the array length. Any help would be appreciated. Not looking for the answer, for a nudge in the right direction.

nameList = [ "Euclid", "Archimedes", "Newton","Descartes", "Fermat", "Turing", "Euler", "Einstein", "Boole", "Fibonacci", "Nash"]
vowelList = ['A', 'a', 'E', 'e', 'I', 'i', 'O', 'o', 'U','u']

z=0
counter = 0
for k in nameList:
    i = 0
    for q in vowelList:
        counter+=nameList[z].count(vowelList[i])
        i+=1
    z=+1
print("The number of vowels in the list is",counter)

Answer 1

You're thinking about this too hard. Relax and let Python do the work:

nameList = [ "Euclid", "Archimedes", "Newton","Descartes", "Fermat", "Turing", "Euler", "Einstein", "Boole", "Fibonacci", "Nash"]
nameStr = ''.join(nameList).lower()
nVowels = len([c for c in nameStr if c in 'aeiou'])
print(f"The number of vowels in the list is {nVowels}.")
>>> The number of vowels in the list is 31.

Plenty of ways to skin a cat in Python :)

Answer 2

Here's something more comprehensible:

nameList = [ "Euclid", "Archimedes", "Newton","Descartes", "Fermat", "Turing", "Euler", "Einstein", "Boole", "Fibonacci", "Nash"]
vowelList = ['A', 'a', 'E', 'e', 'I', 'i', 'O', 'o', 'U','u']


counter = 0
for name in nameList:
    for char in name:
        for vowel in vowelList:
            if char == vowel:
                counter += 1
print("The number of vowels in the list is",counter)

The number of vowels in the list is 31