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Counting Time of code running Python

Tags:

python

time

How could I knwow the execution time of a code in Python in microseconds? I have tried time.time and timeit.timeit but I can't have a good output

like image 334
user3250719 Avatar asked Dec 12 '22 06:12

user3250719


1 Answers

Try this,

import time
def main():
    print [i for i in range(0,100)]
    
start_time = time.clock()
main()
print time.clock() - start_time, "seconds"

Output:

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
0.00255163020819 seconds

Update

Don't forget to import time

Place this line start_time = time.clock() before your code and place this

print time.clock() - start_time, "seconds" at the end of code.

Update

# Top Of script file.
def main():
        print [i for i in range(0,100)]

start_time = time.clock()
#YOUR CODE HERE - 1

main()

#YOUR CODE HERE - N
print time.clock() - start_time, "seconds"

You can also write decorator for measuring time,

import time


def dec(func):
    def wrapper(*args, **kwargs):
        start = time.time()
        func(*args, **kwargs)
        end = time.time()
        print(end - start)
    return wrapper


@dec
def test():
    for i in range(10):
        pass


test()
# output shows here 
like image 52
Nishant Nawarkhede Avatar answered Dec 30 '22 06:12

Nishant Nawarkhede