for a simple data structure such as so:
ID parentID Text Price
1 Root
2 1 Flowers
3 1 Electro
4 2 Rose 10
5 2 Violet 5
6 4 Red Rose 12
7 3 Television 100
8 3 Radio 70
9 8 Webradio 90
For reference, the hierarchy tree looks like this:
ID Text Price
1 Root
|2 Flowers
|-4 Rose 10
| |-6 Red Rose 12
|-5 Violet 5
|3 Electro
|-7 Television 100
|-8 Radio 70
|-9 Webradio 90
I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so:
ID parentID Text Price NoOfChildren
1 Root 8
2 1 Flowers 3
3 1 Electro 3
4 2 Rose 10 1
5 2 Violet 5 0
6 4 Red Rose 12 0
7 3 Television 100 0
8 3 Radio 70 1
9 8 Webradio 90 0
I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here.
SELECT department, COUNT(*) AS "Number of employees" FROM employees WHERE state = 'CA' GROUP BY department; Because you have listed one column in your SELECT statement that is not encapsulated in the COUNT function, you must use a GROUP BY clause.
SELECT COUNT(*) FROM table_name; The COUNT(*) function will return the total number of items in that group including NULL values. The FROM clause in SQL specifies which table we want to list. You can also use the ALL keyword in the COUNT function.
Use hierarchyid as a data type to create tables with a hierarchical structure, or to describe the hierarchical structure of data that is stored in another location. Use the hierarchyid functions in Transact-SQL to query and manage hierarchical data.
SQL – count() with Group By clause The count() function is an aggregate function use to find the count of the rows that satisfy the fixed conditions. The count() function with the GROUP BY clause is used to count the data which were grouped on a particular attribute of the table.
Using a CTE would get you what you want.
COUNT
the items for each root.JOIN
these again with your original table to produce the results.Test Data
DECLARE @Data TABLE (
ID INTEGER PRIMARY KEY
, ParentID INTEGER
, Text VARCHAR(32)
, Price INTEGER
)
INSERT INTO @Data
SELECT 1, Null, 'Root', NULL
UNION ALL SELECT 2, 1, 'Flowers', NULL
UNION ALL SELECT 3, 1, 'Electro', NULL
UNION ALL SELECT 4, 2, 'Rose', 10
UNION ALL SELECT 5, 2, 'Violet', 5
UNION ALL SELECT 6, 4, 'Red Rose', 12
UNION ALL SELECT 7, 3, 'Television', 100
UNION ALL SELECT 8, 3, 'Radio', 70
UNION ALL SELECT 9, 8, 'Webradio', 90
SQL Statement
;WITH ChildrenCTE AS (
SELECT RootID = ID, ID
FROM @Data
UNION ALL
SELECT cte.RootID, d.ID
FROM ChildrenCTE cte
INNER JOIN @Data d ON d.ParentID = cte.ID
)
SELECT d.ID, d.ParentID, d.Text, d.Price, cnt.Children
FROM @Data d
INNER JOIN (
SELECT ID = RootID, Children = COUNT(*) - 1
FROM ChildrenCTE
GROUP BY RootID
) cnt ON cnt.ID = d.ID
Consider using a modified preorder tree traversal way of storing the hierarchical data. See http://www.sitepoint.com/hierarchical-data-database/
Determining number of children for any node then becomes a simple:
SELECT (right-left-1) / 2 AS num_children FROM ...
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With