I need count the number of times in the even lines of the file.txt the letter 'b' or 'B' appears, e.g. for the file.txt like:
everyB or gbnBra
uitiakB and kanapB bodddB
Kanbalis astroBominus
I got the first part but I need to count these b or B letters and I do not know how to count them together
awk '!(NR%2)' file.txt
If N is even then the count of both odd and even numbers will be N/2. If N is odd, If L or R is odd, then the count of the odd numbers will be N/2 + 1, and even numbers = N – countofOdd. Else, the count of odd numbers will be N/2 and even numbers = N – countofOdd.
B (70-74%): Work shows some limitations in coverage and some minor errors in fact or credible interpretation.
Any number that can be exactly divided by 2 is called as an even number. Even numbers always end up with the last digit as 0, 2, 4, 6 or 8. Some examples of even numbers are 2, 4, 6, 8, 10, 12, 14, 16. These are even numbers as these numbers can easily be divided by 2.
$ awk '!(NR%2){print gsub(/[bB]/,"")}' file
4
Could you please try following, one more approach with awk
written on mobile will try it in few mins should work but.
awk -F'[bB]' 'NR%2 == 0{print (NF ? NF - 1 : 0)}' Input_file
Thanks to @Ed sir for solving zero matches found line problem in comments.
In a single awk:
awk '!(NR%2){gsub(/[^Bb]/,"");print length}' file.txt
gsub(/[^Bb]/,"")
deletes every character in the line the line except for B and b.
print length
prints the length of the resulting string.
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