I want to copy the rows 0, 2 and 4 of my matrix A into B, in this order. Let A = [a0, a1, a2, a3, a4]^T , with a_i being row-vectors, then B should be: [a0, a2, a4]^T.
The code below does what I want but I wonder whether there is a prettier solution (maybe using Eigen)?
#include <iostream>
#include <vector>
#include <opencv/cv.h>
int main(int argc, char **argv) {
const int num_points = 5;
const int vec_length = 3;
cv::Mat A(num_points, vec_length, CV_32FC1);
cv::RNG rng(0); // Fill A with random values
rng.fill(A, cv::RNG::UNIFORM, 0, 1);
// HACK Ugly way to fill that matrix .
cv::Mat B = cv::Mat(3,vec_length, CV_32FC1);
cv::Mat tmp0 = B(cv::Rect(0,0,vec_length,1));
cv::Mat tmp1 = B(cv::Rect(0,1,vec_length,1));
cv::Mat tmp2 = B(cv::Rect(0,2,vec_length,1));
A.row(0).copyTo(tmp0);
A.row(2).copyTo(tmp1);
A.row(4).copyTo(tmp2);
std::cout << "A: " << A << std::endl;
std::cout << "B: " << B << std::endl;
return 0;
}
The way in OpenCV 2.4.1 is:
A.row(0).copyTo(B.row(0));
A.row(2).copyTo(B.row(1));
A.row(4).copyTo(B.row(2));
I found push_back
.
Create B
with size 0 x vec_length
and then use push_back
to add the selected rows from A
:
#include <iostream>
#include <vector>
#include <opencv/cv.h>
int main(int argc, char **argv) {
const int num_points = 5;
const int vec_length = 3;
cv::Mat A(num_points, vec_length, CV_32FC1);
cv::RNG rng(0); // Fill A with random values
rng.fill(A, cv::RNG::UNIFORM, 0, 1);
cv::Mat B = cv::Mat(0,vec_length, CV_32FC1);
B.push_back(A.row(0));
B.push_back(A.row(2));
B.push_back(A.row(4));
std::cout << "A: " << A << std::endl;
std::cout << "B: " << B << std::endl;
return 0;
}
Since they are non-contiguous I don't think there's any shortcut. In this particular case you could make the code cleaner with a loop:
for (int i=0; i<3; i++) {
cv::Mat tmp = B(cv::Rect(0,i,vec_length,1));
A.row(i * 2).copyTo(tmp);
}
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