Converting Typesafe Config type to java.util.Properties

Question

The title talks by itself, I have a Config object (from https://github.com/typesafehub/config) and I want to pass it the a constructor which only supports java.util.Properties as argument. Is there an easy way to convert a Config to a Properties object ?

Answer 1

Here is a way to convert a typesafe Config object into a Properties java object. I have only tested it in a simple case for creating Kafka properties.

Given this configuration in application.conf

kafka-topics {
  my-topic {
    zookeeper.connect = "localhost:2181",
    group.id = "testgroup",
    zookeeper.session.timeout.ms = "500",
    zookeeper.sync.time.ms = "250",
    auto.commit.interval.ms = "1000"
  }
}

You can create the corresponding Properties object like that:

import com.typesafe.config.{Config, ConfigFactory}
import java.util.Properties
import kafka.consumer.ConsumerConfig

object Application extends App {

  def propsFromConfig(config: Config): Properties = {
    import scala.collection.JavaConversions._

    val props = new Properties()

    val map: Map[String, Object] = config.entrySet().map({ entry =>
      entry.getKey -> entry.getValue.unwrapped()
    })(collection.breakOut)

    props.putAll(map)
    props
  }

  val config = ConfigFactory.load()

  val consumerConfig = {
    val topicConfig = config.getConfig("kafka-topics.my-topic")
    val props = propsFromConfig(topicConfig)
    new ConsumerConfig(props)
  }

  // ...    
}

The function propsFromConfig is what you are mainly interested in, and the key points are the use of entrySet to get a flatten list of properties, and the unwrapped of the entry value, that gives an Object which type depends on the configuration value.