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Converting NSData to Integer in Swift

In Objective-C the code looked liked this and worked flawlessly,

NSInteger random = arc4random_uniform(99) + 1 
NSData *data = [NSData dataWithBytes:& random length: sizeof(random)];
int value = *(int*)([data bytes]);

How can this be done in Swift?

like image 303
dhint4 Avatar asked Oct 07 '14 02:10

dhint4


5 Answers

Like this:

var src: NSInteger = 2525
var out: NSInteger = 0

let data = NSData(bytes: &src, length: sizeof(NSInteger))
data.getBytes(&out, length: sizeof(NSInteger))
println(out) // ==> 2525
like image 198
findall Avatar answered Nov 18 '22 21:11

findall


In Swift 4:

There are a couple of things to consider when extracting an integer value from a Data stream. Signedness and Endianess. So I came up with a function in an extension to Data that infers Signedness from the type of integer you want to extract and passes Endianess and Index as parameters. The types of integers that can be extracted are all that conform to FixedWidthInteger protocol.

Reminder: This function will not check if the Index range is inside the bounds of the Data buffer so it may crash depending on the size of the type being extracted in relation to the end of the buffer.

extension Data {
    enum Endianness {
        case BigEndian
        case LittleEndian
    }
    func scanValue<T: FixedWidthInteger>(at index: Data.Index, endianess: Endianness) -> T {
        let number: T = self.subdata(in: index..<index + MemoryLayout<T>.size).withUnsafeBytes({ $0.pointee })
        switch endianess {
        case .BigEndian:
            return number.bigEndian
        case .LittleEndian:
            return number.littleEndian
        }
    }
}

Example:

let data = Data(bytes: [0xFF,0x1F,0x1F,0xFF])

let number1 = data.scanValue(at: 0, endianess: .LittleEndian) as UInt16
let number2 = data.scanValue(at: 0, endianess: .BigEndian) as UInt16

let number3: Int16 = data.scanValue(at: 2, endianess: .LittleEndian)
let number4: Int16 = data.scanValue(at: 2, endianess: .BigEndian)

Results:

number1 is 8191
number2 is 65311
number3 is -225
number4 is 8191

Observe the function calls to see how the type to be extracted is inferred. Of course Endianess doesn't make sense for Int8 or UInt8, but the function works as expected.

Values can later be cast to Int if needed.

like image 44
Gustavo Seidler Avatar answered Nov 18 '22 23:11

Gustavo Seidler


You can extend Data type, create a generic method, get the bytes and cast it or set the resulting type explicitly as needed:

extension Data {
    func object<T>(at index: Index = 0) -> T {
        subdata(in: index..<self.index(index, offsetBy: MemoryLayout<T>.size))
        .withUnsafeBytes { $0.load(as: T.self) }
    }
}

extension Numeric {
    var data: Data {
        var source = self
        return Data(bytes: &source, count: MemoryLayout<Self>.size)
    }
}

let data = Data([0xFF, 0x1F])   // 2 bytes

let uint16: UInt16 = data.object()      // 8191  littleEndian
let number1 = uint16.littleEndian       // 8191
let number2 = uint16.bigEndian          // 65311

let int16 = data.object() as Int16      // 8191   littleEndian
let number3 = int16.littleEndian        // 8191
let number4 = int16.bigEndian           // -225

print(number1) // 8191
print(number2) // 65311
print(number3) // 8191
print(number4) // -225

Testing with Int

let random = Int.random(in: 1...100)    // 15 UInt32
let data = random.data                  // 8 bytes  [15, 0, 0, 0, 0, 0, 0, 0]

Testing with UInt32

let random = UInt32.random(in: 1...100)  // 90 UInt32
let data = random.data                   // 4 bytes  [90, 0, 0, 0]

Testing with Double

let random = Double.random(in: 0...1)  // 0.2463145485351322 Double
let data = random.data                 // 8 bytes  [12, 99, 62, 49, 60, 135, 207, 63]

If you want to extract a subdata:

let data = Data([0xFF, 0x1F, 0x1F, 0xFF])      // 4 bytes

let uint16: UInt16 = data.object(at: 2)        //  65311 littleEndian
let number1 = uint16.littleEndian              // 65311
let number2 = uint16.bigEndian                 // 8191

let int16: Int16 = data.object(at: 2)          // -225   littleEndian
let number3 = int16.littleEndian               // -225
let number4 = int16.bigEndian                  // 8191

number1 // 65311
number2 // 8191
number3 // -225
number4 // 8191
like image 40
Leo Dabus Avatar answered Nov 18 '22 21:11

Leo Dabus


For Swift 3, you can do this (little endian, but similar for big):

func getInt(fromData data: Data, start: Int) -> Int32 {
  let intBits = data.withUnsafeBytes({(bytePointer: UnsafePointer<UInt8>) -> Int32 in
    bytePointer.advanced(by: start).withMemoryRebound(to: Int32.self, capacity: 4) { pointer in
      return pointer.pointee
    }
  })
  return Int32(littleEndian: intBits)
}

You can modify this, add generics, etc. to fit other primitive types (and vary it depending on the endianness of the data bytes).

like image 6
benasher44 Avatar answered Nov 18 '22 22:11

benasher44


You might find this method useful if you are doing it a lot:

func readInteger<T : IntegerType>(data : NSData, start : Int) -> T {
    var d : T = 0
    data.getBytes(&d, range: NSRange(location: start, length: sizeof(T)))
    return d
}

The function takes as a parameter the start position in the data to read the numeric type and it returns a value of the a type inferred from whatever you are assigning it to.

For example:

let i : UInt32 = readInteger(data, 10);

reads an 4 byte integer from position 10 in the data.

If you change UInt32 to UInt16 it will read two bytes.

like image 5
rghome Avatar answered Nov 18 '22 22:11

rghome