Converting Boolean value to Integer value in swift 3

Question

I was converting from swift 2 to swift 3. I noticed that I cannot convert a boolean value to integer value in swift 3 :\ .

let p1 = ("a" == "a") //true  print(true)           //"true\n" print(p1)             //"true\n"  Int(true)             //1  Int(p1)               //error 

For example these syntaxes worked fine in swift 2. But in swift 3, print(p1) yields an error.

The error is error: cannot invoke initializer for type 'Int' with an argument list of type '((Bool))'

I understand why the errors are happening. Can anyone explain what is the reason for this safety and how to convert from Bool to Int in swift 3?

Answer 1

You could use the ternary operator to convert a Bool to Int:

let result = condition ? 1 : 0 

result will be 1 if condition is true, 0 is condition is false.

Answer 2

Swift 5

Bool -> Int

extension Bool {     var intValue: Int {         return self ? 1 : 0     } } 

Int -> Bool

extension Int {     var boolValue: Bool {         return self != 0      } }