Converting BigInteger to binary string

Question

Can we convert Biginteger to binary string

   String s1 = "0011111111101111111111111100101101111100110000001011111000010100";    String s2 = "0011111111100000110011001100110011001100110011001100110011001100";    BigInteger bi1, bi2, bi3;    bi1 = new BigInteger(s1,2);    bi2 = new BigInteger(s2,2);    bi3 = bi1.xor(bi2); 

How to convert bi3 to binary string

Answer 1

You can use toString(radix) for that:

String s3 = bi3.toString(2); 

Answer 2

import java.math.BigInteger; import java.util.Scanner;

public static void main(String[] args) {     Scanner in = new Scanner(System.in);     System.out.println("Enter a Number: ");     String n = in.next();     BigInteger nn = new BigInteger(n);     if(nn.compareTo(BigInteger.ZERO)<0){         System.out.println("Number cannot be less than 0");     }else{         System.out.println("Convert to binary is:");         print2Binaryform(nn);         System.out.println("");     } } private static void print2Binaryform(BigInteger number) {     BigInteger reminder2;     if(number.compareTo(BigInteger.ONE)<=0){         System.out.print(number);         return;     }     reminder2 = number.mod(new BigInteger(""+2));     print2Binaryform(new BigInteger(""+number.divide(new BigInteger("2"))));     System.out.print(reminder2); }