Converting Action method call to async Action method call

Question

I've this method

public void Execute(Action action) {     try     {         action();     }     finally     {     } } 

and I need to convert it to an async method call like this one

public async Task ExecuteAsync(Action action) {     try     {         await action();     }     finally     {     } } 

The problem with the code above is that the compiler issue the following error

The 'await' operator can only be used within an async lambda expression. Consider marking this lambda expression with the 'async' modifier.

Answer 1

If you want to await on a delegate, it has to be of type Func<Task> or Func<Task<T>>. An Action is equivalent into a void Action() named method. You can't await on void, yet you can await Task Func() or Task<T> Func:

public async Task ExecuteAsync(Func<Task> func) {     try     {         await func();     }     finally     {     } } 

If this can't be done, it means that internally the method isn't truly asynchronous, and what you actually want to do is execute the synchronous delegate on a thread-pool thread, which is a different matter, and isn't really executing something asynchronously. In that case, wrapping the call with Task.Run will suffice.