I have a String
that could be in many different formats
. I need to be able to recognize the actual type of the value at runtime
and then transform the value to that type.
For example. If I have a String
Fri Feb 08 07:30:00 GMT 2013
this is actually a Date
and a the String
should be transformed into a date object
and returned as such.
My current solution to this problem is to 'try' to convert it to a data type, if the conversion succeeds then all is good, if the conversion fails then move on to the next conversion attempt. This works, but is ugly and un-maintainable and I'm sure a better solution already exists out there.
Thanks.
Changing any data type into a String Any built-in data type can be converted into its string representation by the str() function. Built-in data type in python include:- int , float , complex , list , tuple , dict etc.
In Python an integer can be converted into a string using the built-in str() function. The str() function takes in any python data type and converts it into a string. But use of the str() is not the only way to do so. This type of conversion can also be done using the “%s” keyword, the .
One effective way to convert a string object into a numeral int is to use the stoi() function. This method is commonly used for newer versions of C++, with is being introduced with C++11. It takes as input a string value and returns as output the integer version of it.
You may use separate regular expression for each data type like this:
private final static Pattern DATE_PATTERN =
Pattern.compile (
"(?:Sun|Mon|Tue|Wed|Thu|Fri|Sat) " +
"(?:Jan|Feb|Mar|Apr|May|June?|July?|Aug|Sept?|Oct|Nov|Dec) " +
"\\d\\d \\d\\d:\\d\\d:\\d\\d \\S+ \\d\\d\\d\\d");
private final static Pattern DOUBLE_PATTERN =
Pattern.compile (
"[\\+\\-]?\\d+\\.\\d+(?:[eE][\\+\\-]?\\d+)?");
private final static Pattern INTEGER_PATTERN =
Pattern.compile (
"[\\+\\-]?\\d+");
public static Object stringToObject (String string)
{
if (DATE_PATTERN.matcher (string).matches ())
return stringToDate (string);
else if (DOUBLE_PATTERN.matcher (string).matches ())
return Double.valueOf (string);
else if (INTEGER_PATTERN.matcher (string).matches ())
return Integer.valueOf (string);
else return string;
}
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