Convert string into Date type on Python [duplicate]

Question

I have this string:

'2012-02-10' # (year-month-day)

and I need it to be as date type for me to use the date function isoweekday().

Does anyone know how I can convert this string into a date?

Answer 1

While it seems the question was answered per the OP's request, none of the answers give a good way to get a datetime.date object instead of a datetime.datetime. So for those searching and finding this thread:

datetime.date has no .strptime method; use the one on datetime.datetime instead and then call .date() on it to receive the datetime.date object.

Like so:

>>> from datetime import datetime >>> datetime.strptime('2014-12-04', '%Y-%m-%d').date() datetime.date(2014, 12, 4) 

Answer 2

You can do that with datetime.strptime()

Example:

>>> from datetime import datetime >>> datetime.strptime('2012-02-10' , '%Y-%m-%d') datetime.datetime(2012, 2, 10, 0, 0) >>> _.isoweekday() 5 

You can find the table with all the strptime directive here.

---

To increment by 2 days if .isweekday() == 6, you can use timedelta():

>>> import datetime >>> date = datetime.datetime.strptime('2012-02-11' , '%Y-%m-%d') >>> if date.isoweekday() == 6: ...     date += datetime.timedelta(days=2) ...  >>> date datetime.datetime(2012, 2, 13, 0, 0) >>> date.strftime('%Y-%m-%d')   # if you want a string again '2012-02-13' 

Answer 3

from datetime import datetime

a = datetime.strptime(f, "%Y-%m-%d")

Answer 4

Use datetime.datetime.strptime:

>>> import datetime
>>> date = datetime.datetime.strptime('2012-02-10', '%Y-%m-%d')
>>> date.isoweekday()
5

Answer 5

>>> from datetime import datetime
>>> year, month, day = map(int, my_date.split('-'))
>>> date_object = datetime(year, month, day)