I cropped an jpeg image, but the cropped image type is
<class 'PIL.Image.Image'>
how can i convert it to
<class 'PIL.JpegImagePlugin.JpegImageFile'>
?
thank you!
import requests
from PIL import Image
from io import BytesIO
img = Image.open(BytesIO(requests.get("https://mamahelpers.co/assets/images/faq/32B.JPG").content))
img2 = img.crop((1,20,50,80))
print(type(img)) # <class 'PIL.JpegImagePlugin.JpegImageFile'>
print(type(img2)) # <class 'PIL.Image.Image'>
If you do not want a pyhsical file, do use a memory file:
import requests
from PIL import Image
from io import BytesIO
img = Image.open(BytesIO(requests.get("https://mamahelpers.co/assets/images/faq/32B.JPG").content))
img2 = img.crop((1,20,50,80))
b = BytesIO()
img2.save(b,format="jpeg")
img3 = Image.open(b)
print(type(img)) # <class 'PIL.JpegImagePlugin.JpegImageFile'>
print(type(img2)) # <class 'PIL.Image.Image'>
print(type(img3)) # <class 'PIL.JpegImagePlugin.JpegImageFile'>
ByteIO is a stream-obj, it is probably wise to close()
it at some point when no longer needed.
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