Convert int to *NSInteger

Question

When using this

NSInteger *myInteger = 45 ; 

I get the warning message Incompatible Integer to pointer conversion sending 'NSInteger' (aka 'int') to parameter of type 'NSInteger *' (aka 'int *') I have read another posts with same warning but did not find proper solution.

Answer 1

NSInteger is not a subclass of NSObject as it might seem, it's a primitive type. Change your code to:

NSInteger a = 45 ; 

And (of course) do not name your variable int

Answer 2

You should use different name then int because it is a name for a special primitive type integer. Like that you cannot name a variable with names like for, while, void... Just use another name(and you should name it to understand what it holds) like:

NSInteger myFirstInteger = 45;    

Note: In your future projects, please name your variables with a meaningful name ,so that you can create a meaningful piece of code which is easy to understand and improve.