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assume I have a 3-element array like this:
A = [1, 2, 3]
How can I convert it to:
B = [1; 2; 3]
in Julia?
205
Reshaping array dimensions in Julia | Array reshape() Method The reshape() is an inbuilt function in julia which is used to return an array with the same data as the specified array, but with different specified dimension sizes.
Arrays in Julia are mutable and hence it allows modification of its content. Elements in arrays can be removed or updated as per requirement.
Create an array filled with the value x . For example, fill(1.0, (10,10)) returns a 10x10 array of floats, with each element initialized to 1.0 . If x is an object reference, all elements will refer to the same object. fill(Foo(), dims) will return an array filled with the result of evaluating Foo() once.
Creating a Vector A Vector in Julia can be created with the use of a pre-defined keyword Vector() or by simply writing Vector elements within square brackets([]). There are different ways of creating Vector. vector_name = [value1, value2, value3,..] or vector_name = Vector{Datatype}([value1, value2, value3,..])
transpose creates an Adjoint object that actually holds a view
julia> A = [1, 2, 3];
julia> A'
1×3 LinearAlgebra.Adjoint{Int64,Array{Int64,1}}:
1 2 3
Wrapping it with collect would make an actual horizontal vector:
julia> collect(A')
1×3 Array{Int64,2}:
99 2 3
You need to however understand that in Julia 1-dimensional Vectors are always vertical while a vector can be also represented by a two-dimensional matrix where one dimension is equal to one:
julia> B=[1 2 3]
1×3 Array{Int64,2}:
1 2 3
julia> C = collect(B')
3×1 Array{Int64,2}:
1
2
3
Finally, each of those can be converted to a standar vector using the vec function or [:] operator:
julia> A == B[:] == C[:] == vec(B) == vec(C) == @view(C[:]) == @view(B[:])
true
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