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Could someone convert the following PostMark curl example to pycurl?
curl -X POST "http://api.postmarkapp.com/email" \
-H "Accept: application/json" \
-H "Content-Type: application/json" \
-H "X-Postmark-Server-Token: ed742D75-5a45-49b6-a0a1-5b9ec3dc9e5d" \
-v \
-d "{From: '[email protected]', To: '[email protected]', Subject: 'Postmark test', HtmlBody: '<html><body><strong>Hello</strong> dear Postmark user.</body></html>'}"
978
Curl Converter automatically generates valid Python code using the Python request library for all provided Curl HTTP headers and Curl data. Enter the Curl command, click Run to execute the command online and check the results. Click Generate Code and select Python to convert the Curl command to Python code.
In Python, cURL transfers requests and data to and from servers using PycURL. PycURL functions as an interface for the libcURL library within Python. Almost every programming language can use REST APIs to access an endpoint hosted on a web server.
You can use something like this. It's a basic implementation but it should work.
import pycurl, json
postmark_url = 'https://api.postmarkapp.com/email'
data = json.dumps({"From": "[email protected]", "To": "[email protected]", "Subject": "Pycurl", "TextBody": "Some text"})
c = pycurl.Curl()
c.setopt(pycurl.URL, github_url)
c.setopt(pycurl.HTTPHEADER, ['X-Postmark-Server-Token: API_TOKEN_HERE','Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()
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