I am using openCV with python to extract contours from an image. Now I need to export these contour paths (list) as an svg paths. How can I achieve this ?
code:
ret,thresh = cv2.threshold(imgray,27,25,0)
contours, hierarchy = cv2.findContours(thresh, cv2.RETR_EXTERNAL , cv2.CHAIN_APPROX_TC89_L1)
print(type(contours)) #type list
the problem has been solved as follows:
c = max(contours, key=cv2.contourArea) #max contour
f = open('path.svg', 'w+')
f.write('<svg width="'+str(width)+'" height="'+str(height)+'" xmlns="http://www.w3.org/2000/svg">')
f.write('<path d="M')
for i in xrange(len(c)):
#print(c[i][0])
x, y = c[i][0]
print(x)
f.write(str(x)+ ' ' + str(y)+' ')
f.write('"/>')
f.write('</svg>')
f.close()
The other answer only save the outmost contour in svg file, which is not my case. To save all the contours found by opencv, you could instead do this:
with open("path.svg", "w+") as f:
f.write(f'<svg width="{w}" height="{h}" xmlns="http://www.w3.org/2000/svg">')
for c in contours:
f.write('<path d="M')
for i in range(len(c)):
x, y = c[i][0]
f.write(f"{x} {y} ")
f.write('" style="stroke:pink"/>')
f.write("</svg>")
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With