Convert char pointer to unsigned char array

Question

I want to convert a char pointer to a unsigned char var, I thought I could do that with just casting but it doesn't work:

char * pch2;
//Code that puts something in pc2
part1 = (unsigned char) pch2;

I've the code to this:

result.part1 = (unsigned char *) pch2;
printf("STRUCT %s\n",result.part1);

result is just a struct with unsigned char arrays.

EDIT:

            pch2 = strtok( ip, "." );

            while( pch2 != NULL ){
                printf( "x %d x: %s\n", i, pch2 );
                pch2[size-1] = '\0';

                if(i == 1)
                    result.part1 = (unsigned char *) pch2;
                if(i == 2)
                    result.part2 = (unsigned char *) pch2;
                if(i == 3)
                    result.part3 = (unsigned char *) pch2;
                if(i == 4)
                    result.part4 = (unsigned char *) pch2;
                i++;
                pch2 = strtok (NULL,".");
            }   
            printf("STRUCT %c\n",result.part1);

Struct:

typedef struct
{
    unsigned char part1;
    unsigned char part2;
    unsigned char part3;
    unsigned char part4;
} res;

Answer 1

you cast to unsigned char not unsigned char* you forgot the *

part1 = (unsigned char*) pch2;

if pch2 is not null terminated the program will crash, if you're lucky, when you use strlen, so you need to null terminate it first before printing using pch2, try this instead:

pch2[size-1] = '\0';  /* note single quote */
result.part1 = (unsigned char *) pch2;

Update: define your structure like so:

typedef struct
{
    const char *part1;
    const char *part2
    const char *part3;
    const char *part4;
} res;

And assign to it without casting at all:

result.part1 = pch2;