Convert char A-Z to corresponding int.

Question

i am trying to convert A char from an array (2nd and 3rd) slot to int value that correspond to eg. A = 1 , B= 2, etc. For A-Z.

I am thinking that the long way will be doing if(x.charAt(i) == 'a'){ int z = 1; } for the whole A - Z which i think it is a very practical method. Is there any method that can do the same thing with a shorter code?

public static void computeCheckDigit(String x){
char [] arr = new char[x.length()];

for(int i=0; i<x.length();i++){
    arr[i] = x.charAt(i);
}


}

Answer 1

Try this:

arr[i] = Character.toLowerCase(x.charAt(i)) - 'a' + 1;

You have to use int Array instead char Array.

public static void main(String[] args) {
    String x = "AbC";
    int[] arr = new int[x.length()];

    for (int i = 0; i < x.length(); i++) {
        arr[i] = Character.toLowerCase(x.charAt(i)) - 'a' + 1;
    }
    System.out.println(Arrays.toString(arr));

}

Output:

[1, 2, 3]