Convert byte slice "[]uint8" to float64 in GoLang

Question

I'm trying to convert a []uint8 byte slice into a float64 in GoLang. I can't find a solution for this issue online. I've seen suggestions of converting to a string first and then to a float64 but this doesn't seem to work, it loses it's value and I end up with zeroes.

Example:

metric.Value, _ = strconv.ParseFloat(string(column.Value), 64) 

And it doesn't work...

Answer 1

For example,

package main  import (     "encoding/binary"     "fmt"     "math" )  func Float64frombytes(bytes []byte) float64 {     bits := binary.LittleEndian.Uint64(bytes)     float := math.Float64frombits(bits)     return float }  func Float64bytes(float float64) []byte {     bits := math.Float64bits(float)     bytes := make([]byte, 8)     binary.LittleEndian.PutUint64(bytes, bits)     return bytes }  func main() {     bytes := Float64bytes(math.Pi)     fmt.Println(bytes)     float := Float64frombytes(bytes)     fmt.Println(float) } 

Output:

[24 45 68 84 251 33 9 64] 3.141592653589793 

Answer 2

I think this example from Go documentation is what you are looking for: http://golang.org/pkg/encoding/binary/#example_Read

var pi float64 b := []byte{0x18, 0x2d, 0x44, 0x54, 0xfb, 0x21, 0x09, 0x40} buf := bytes.NewReader(b) err := binary.Read(buf, binary.LittleEndian, &pi) if err != nil {   fmt.Println("binary.Read failed:", err) } fmt.Print(pi) 

Prints 3.141592653589793