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Convert builtin function type to method type (in Python 3)

Consider a simple function like

def increment(self):
    self.count += 1

which is run through Cython and compiled into an extension module. Suppose now I'd like to make this function a method on a class. For example:

class Counter:
    def __init__(self):
        self.count = 0

from compiled_extension import increment
Counter.increment = increment

Now this will not work, as the calling convention at the C level will be broken. For example:

>>> c = Counter()
>>> c.increment()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: increment() takes exactly one argument (0 given)

But in Python 2, we can convert the function to an unbound method by doing:

Counter.increment = types.MethodType(increment, None, Counter)

How can I accomplish this same thing in Python 3?

One simple way is to use a slim wrapper:

from functools import wraps
def method_wraper(f):
    def wrapper(*args, **kwargs):
        return f(*args, **kwargs)
    return wraps(f)(wrapper)

Counter.increment = method_wrapper(increment)

Is there a more efficient way to do it?

like image 486
bfroehle Avatar asked May 24 '12 01:05

bfroehle


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1 Answers

First thing is getting the names correctly:

>>> def increment(obj):
...     obj.count += 1
...
>>> class A(object):
...     def __init__(self):
...         self.count = 0
...
>>> o = A()
>>> o.__init__
<bound method A.__init__ of <__main__.A object at 0x0000000002766EF0>>
>>> increment
<function increment at 0x00000000027797C8>

So proper names are functions and bound methods. Now you can look for how to Bind an Unbound Method and you will probably end up reading about descriptors:

In general, a descriptor is an object attribute with "binding behavior", one whose attribute access has been overridden by methods in the descriptor protocol. Those methods are __get__, __set__, and __delete__. If any of those methods are defined for an object, it is said to be a descriptor.

You can easily transform function to method by just using different invocation of __get__

>>> increment.__get__(None, type(None))
<function increment at 0x00000000027797C8>
>>> increment.__get__(o, type(o))
<bound method A.increment of <__main__.A object at 0x00000000027669B0>>

And it works like a charm:

>>> o = A()
>>> increment.__get__(None, type(None))(o)
>>> o.count
1
>>> increment.__get__(o, type(o))()
>>> o.count
2

You can easily add these newly bounded methods to objects:

def increment(obj):
    obj.count += 1

def addition(obj, number):
    obj.count += number

class A(object):
    def __init__(self):
        self.count = 0

o = A()
o.inc = increment.__get__(o)
o.add = addition.__get__(o)
print(o.count) # 0
o.inc()
print(o.count) # 1
o.add(5)
print(o.count) # 6

Or create your own descriptor that will will convert function to bound method:

class BoundMethod(object):
    def __init__(self, function):
        self.function = function

    def __get__(self, obj, objtype=None):
        print('Getting', obj, objtype)
        return self.function.__get__(obj, objtype)

class B(object):
    def __init__(self):
        self.count = 0

    inc = BoundMethod(increment)
    add = BoundMethod(addition)


o = B()
print(o.count) # 0
o.inc()
# Getting <__main__.B object at 0x0000000002677978> <class '__main__.B'>
print(o.count) # 1
o.add(5) 
# Getting <__main__.B object at 0x0000000002677978> <class '__main__.B'>
print(o.count) # 6

And you also can see that this is nicely consistent with function/bound method principles:

Class dictionaries store methods as functions. In a class definition, methods are written using def and lambda, the usual tools for creating functions. The only difference from regular functions is that the first argument is reserved for the object instance. By Python convention, the instance reference is called self but may be called this or any other variable name.

To support method calls, functions include the __get__() method for binding methods during attribute access. This means that all functions are non-data descriptors which return bound or unbound methods depending whether they are invoked from an object or a class.

And functions becomes bound method during instance initialization:

>>> B.add
# Getting None <class '__main__.B'>
<function addition at 0x00000000025859C8>
>>> o.add
# Getting <__main__.B object at 0x00000000030B1128> <class '__main__.B'>
<bound method B.addition of <__main__.B object at 0x00000000030B1128>>
like image 140
Vyktor Avatar answered Oct 26 '22 10:10

Vyktor