Convert all keys of a dictionary into lowercase [duplicate]

Question

alphabet = {'A':1, 'B': 2, 'C': 3, 'D':4, 'E': 5, 'F': 6, 'G':7, 'H':8, 'I':9, 'J':10,             'K':11, 'L':12, 'M':13, 'N':14, 'O':15,'P': 16,'Q': 17,'R': 18,'S':19,'T':20,             'U': 21, 'V':22, 'W':23, 'X': 24, 'Y':25, 'Z':26, ' ':27} 

Is there any way to convert all of the keys into lowercase? Note: There is a space at the end of the dict.

Answer 1

use dict comprehensions

alphabet =  {k.lower(): v for k, v in alphabet.items()} 

Answer 2

Just use a comprehension to run through the dictionary again and convert all keys to lowercase.

alphlower = {k.lower(): v for k, v in alphabet.iteritems()} 

Result

{' ': 27, 'a': 1, 'c': 3, 'b': 2, 'e': 5, 'd': 4, 'g': 7, 'f': 6, 'i': 9, 'h': 8, 'k': 11, 'j': 10, 'm': 13, 'l': 12, 'o': 15, 'n': 14, 'q': 17, 'p': 16, 's': 19, 'r': 18, 'u': 21, 't': 20, 'w': 23, 'v': 22, 'y': 25, 'x': 24, 'z': 26}

If you are using python 3, then use alphabet.items() instead of iteritems.