I'd like to convert a vector<char>
to a std::string
and do a conversion one the way.
I'm almost there, but the result of the code below is a vector<string>
, while I'd like to have one string (a concatenation of all the string parts in the vector).
See my code example for details.
string ConvertHexToAscii(const char input)
{
std::ostringstream oss;
oss << std::hex << std::setw(2) << std::setfill('0') << static_cast<int>(input);
return oss.str();
}
vector<char> readBuffer; // this is my input
readBuffer.push_back(0x1c);
readBuffer.push_back(0x09);
vector<string> resultVec;
std::transform(readBuffer.begin(), readBuffer.end()
, back_inserter(resultVec)
, ConvertHexToAscii);
// resultVec[0] = "1C";
// resultVec[1] = "09";
The result I need is a string containing "1C09". How to achieve that with std::transform
?
Using std::accumulate Another option to convert a vector to a string is using the standard function std::accumulate , defined in the header <numeric> . We can overwrite its default operation by providing a binary predicate to perform the concat operation on two strings and return the result.
Returning a Vector Pointervector<string> *v = fn(&store); respectively. Note the presence and position of * in the return type of the function definition.
You were almost there; this works:
std::stringstream sstr;
std::transform(
input.begin(), input.end(),
std::ostream_iterator<std::string>(sstr, ""),
ConvertHexToAscii);
But unfortunately this instantiates quite a lot of string streams, which is inefficient. Ideally, the ConvertHexToAscii
(misnamed, by the way! C++ doesn’t know about encodings) function would directly use the underlying stream.
#include <iostream>
#include <vector>
#include <iomanip>
#include <sstream>
#include <numeric>
std::string ConvertHexToAscii(std::string acc, char input)
{
std::ostringstream oss;
oss << std::hex << std::setw(2) << std::setfill('0') << static_cast<int>(input);
return acc + oss.str();
}
int main() {
std::vector<char> readBuffer; // this is my input
readBuffer.push_back(0x1c);
readBuffer.push_back(0x09);
std::cout << std::accumulate(readBuffer.begin(), readBuffer.end()
, std::string(), ConvertHexToAscii) << std::endl;
return 0;
}
create your own back_insert_iterator (look at the code in your stl lib, it's fairly simple) for string types of which operator = is defined as
template< class string_type, class value_type >
class back_insert_iterator
{
public:
back_insert_iterator< _string_type >& operator = ( const value_type& val )
{
container->append( val )
return *this;
}
};
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