Convert a epoch timestamp to yyyy/mm/dd hh:mm

Question

I'm given a timestamp (time since the epoch) and I need to convert it into this format:

yyyy/mm/dd hh:mm

I looked around and it seems like everyone else is doing this the other way around (date to timestamp).

If your answer involves dateutil that would be great.

Answer 1

Using datetime instead of dateutil:

import datetime as dt
dt.datetime.utcfromtimestamp(seconds_since_epoch).strftime("%Y/%m/%d %H:%M")

An example:

import time
import datetime as dt

epoch_now = time.time()
sys.stdout.write(str(epoch_now))
>>> 1470841955.88

frmt_date = dt.datetime.utcfromtimestamp(epoch_now).strftime("%Y/%m/%d %H:%M")
sys.stdout.write(frmt_date)
>>> 2016/08/10 15:09

EDIT: strftime() used, as the comments suggested.