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Conversion from void* to the pointer of the base class

Tags:

c++

casting

I have some hierarchy: base, derived classes and some structure storing user data as void*. That void can store both Base and Derived classes pointers. Main problem that I do not know what is stored there base or derived pointer.


class Base
{
public:
  int type;
};
class Derived: public Base
{};

Base* base;//init base pointer Derived* derived;//init derived pointer void* base_v = base; void* derived_v = derived; //void pointers are correct. They point to base and derived variables.

//try to get type field after converting pointers back Derived* d_restored = (Derived*)derived_v;//d_restored correct Base* b_restored = (Base*)base_v;//b_restored correct Base* d_restored_to_base = (Base*)derived_v;// INCORRECT

How to convert void* to get [type] field for both pointers? Thanks in advance.

like image 269
Yevhen Avatar asked Mar 26 '11 20:03

Yevhen


2 Answers

void*'s can only be converted back to their original type. When you store a Derived* in a void*, you can only cast back to Derived*, not Base*.

This is especially noticeable with multiple inheritance, as your derived object might not necessarily be at the same address as your base. If you really need to store things (and retrieve things) with void*, always cast to the base type first, so you have a stable way of getting the object back:

#include <iostream>

struct base { int type; };
struct intruder { int iminyourclassstealingyourbase; };
struct derived : intruder, base {};

int main()
{
    derived d; d.type = 5;

    void* good = (base*)&d;
    void* bad = &d;

    base* b1 = (base*)good;
    base* b2 = (base*)bad;

    std::cout << "good: " << b1->type << "\n";
    std::cout << "bad: " << b2->type << "\n";
}

If you then want to go back to the derived type, use a dynamic_cast (or static_cast if you're guaranteed it has to be of the derived type.)

like image 172
GManNickG Avatar answered Oct 20 '22 04:10

GManNickG


When you use multiple inheritance, the resulting object is internally acting much like a composite, conceptually something like this:

struct Derived {
  Base1 b1;
  Base2 b2;
};

You will get different addresses for your instance of Derived depending on whether you cast it to Base1 or Base2. So, you can't reliably do what you want to do. You'll need to keep a pointer to one of the involved types, and use dynamic_cast

Alternatively, you could make your own rules - saying that you always store the address of your instance casted to a specific base class, and always cast back to this base class. This is very error-prone, and I'd strongly recommend that you try to store a pointer to a common base class if at all possible.

like image 41
Erik Avatar answered Oct 20 '22 05:10

Erik