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I want to request to my server running in python flask with file and some meta information. Hence my request content-Type will be 'multipart/form-data. Is there a way i can set the content type of file like image/jpg, image/gif etc... How do i set the content-type for the file. Is it possible or not
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To send the Content-Type header using Curl, you need to use the -H command-line option. For example, you can use the -H "Content-Type: application/json" command-line parameter for JSON data. Data is passed to Curl using the -d command-line option.
Python requests are generally used to fetch the content from a particular resource URI. Whenever we make a request to a specified URI through Python, it returns a response object. Now, this response object would be used to access certain features such as content, headers, etc.
Client Request with Content-Type Header [Python Code] The 'Content-Type: application/json' header tells the server that the request body contains a JSON string. The Python code was automatically generated for the Client Request Content Type Header example.
If you make each file specification a tuple, you can specify the mime type as a third parameter:
files = {
'file1': ('foo.gif', open('foo.gif', 'rb'), 'image/gif'),
'file2': ('bar.png', open('bar.png', 'rb'), 'image/png'),
}
response = requests.post(url, files=files)
You can give a 4th parameter as well, which must be a dictionary with additional headers for each part.
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reference
import requests
url = "http://png_upload_example/upload"
# files = [(<key>, (<filename>, open(<file location>, 'rb'), <content type>))]
files = [('upload', ('thumbnail.png', open('thumbnail.png', 'rb'), 'image/png'))]
response = requests.request("POST", url, files = files)
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