const for array size expressions on argument

Question

I have the following C code example:

int f(const int farg[const 5])
{
}

What does the additional const for the array size do? And what is the difference when I omit the const there?

Answer 1

int d(const int darg[5])

Means darg is a pointer to const int.

int e(int earg[const 5])

Means earg is a const pointer to int. This is a c99 feature. T A[qualifier-list e] is equivalent as T * qualifier-list A in the parameter declaration.

And of course (from above):

int f(const int farg[const 5])

Means farg is a const pointer to const int.