I have two numpy arrays, for example:
a = [[1,2,3],[4,5,6],[7,8,9]]
b = [[11,12,13],[14,15,16],[17,18,19]]
Which are channels of the same image. I would like to get the "connected" channels array in a as pythonic way as possible. wanted outcome:
c = [[[1,11],[2,12],[3,13]],
[[4,14],[5,15],[6,16]],
[[7,17],[8,18],[9,19]]]
What Iv'e tried: I created an array of the same size and looped over both the source array to connect them.
for x in range(len(a)):
for y in range(len(a[x])):
c[x][y] = [a[x][y],b[x][y]]
What I need: I would love to find a more efficient, modular and pythonic way of implementing this.
You can use np.stack on the second axis:
>>> np.stack((a,b),axis=2)
array([[[ 1, 11],
[ 2, 12],
[ 3, 13]],
[[ 4, 14],
[ 5, 15],
[ 6, 16]],
[[ 7, 17],
[ 8, 18],
[ 9, 19]]])
Checking that it's the same as your c array:
c = np.array([[[1,11],[2,12],[3,13]],
[[4,14],[5,15],[6,16]],
[[7,17],[8,18],[9,19]]])
>>> (c == np.stack((a,b),axis=2)).all()
True
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