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Following code compiles and gives 1 as output, its a bit confusing for me. I tried javap for this but from there also I couldn't figure out. I have checked for similar posts but couldn't find out similar question here.
Take look at the code:
int i = (byte) + (char) - (int) + (long) - 1;
System.out.println(i);
here is bytecode for it
Compiled from "Test.java"
public class Test {
public Test();
public static void main(java.lang.String[]);
}
How the types are working here? is it dependent of size of datatype? How the code is working?
535
Code duplicate – identical or similar source code Source code that is used in identical form several times within a piece of software is called a code duplicate – alternatively also a software clone or source code clone. Similar code sections or fragments are also considered duplicates.
Duplication is bad, but… It isn't a question of whether you'll remember: it's a question of when you'll forget.” Which makes perfect sense. It's time well spent when you try to make your code streamlined and readable. You'll end up with a cleaner, easier-to-maintain, and more extensible code base as a result.
It's safe to say that duplicate code makes your code awfully hard to maintain. It makes your codebase unnecessary large and adds extra technical debt. On top of that, writing duplicate code is a waste of time that could have been better spent.
This is just a sequence of unary + and - operations mixed with type casts.
You start with -1, cast it to a long, the unary plus does nothing, cast it to an int, unary minus (value is now +1), cast to char, unary +, cast to byte.
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