I am using wnameless/oracle-xe-11g docker image to create a new image file. And when I create a container from the new image I want the impdp command to be executed. How can this be achieved via Dockerfile?
Here is my Docker file
Dockerfile
# Base Image
FROM wnameless/oracle-xe-11g
# Create database_dump folder at / -location
RUN mkdir ../database_dumps
# Copy the dump file and put it into database_dumps created earlier
COPY dump_file ../database_dumps
# Give permission to user oracle on oracle folder to create tablespace
and related operations
RUN chown -R oracle /u01/app/oracle/oradata/XE
# RUN the database initial sql.(create tablespace, create user etc)
ADD init.sql /docker-entrypoint-initdb.d/
# Here is where I want to call the impdp command. when a container is
created from this image.
For now I am doing this manually by ssh-ing into the container and running the impdp. I tried to do it using the
CMD ["impdp", "system/oracle NOLOGFILE=Y DIRECTORY.."]
but does not work and throws exception.
So my question is "Is this possible"? If yes can you please provide the code example of how this can be achieved?
Thanks,
Update: The exception is not when creating the image but when trying to create a container from it.
So for example If I include this as the last line of my docker file
CMD [“impdp”, “system/oracle NOLOGFILE=Y DIRECTORY=expdp_dir
DUMPFILE=SAMPLE_MASTER.EXPDP SCHEMAS=c##sample transform=OID:n”]
Then do a
docker build -t my/my_oracle .
and run it as
docker run -d -p 49160:22 -p 49161:1521 my/my_oracle
and check for
docker logs <container_id>
I see that
/bin/sh: 1: ["impdp", : not found
The docker container create (or shorthand: docker create ) command creates a new container from the specified image, without starting it. When creating a container, the docker daemon creates a writeable container layer over the specified image and prepares it for running the specified command.
A Dockerfile contains a script of instructions that Docker uses to create a container image. In the app directory, the same location as the package.json file, create a file named Dockerfile . You can use the following commands below to create a Dockerfile based on your operating system.
Ok, I have now figured how to make it happen, after much of experimenting,reading how the cmd
works (finally) and the help/inputs provided by the above comments from other users.
Basically Docker runs only one CMD
(from the docs). So if I create a dockerfile from wnameless/oracle-xe-11g
as
From wnameless/oracle-xe-11g
...
...
CMD ["impdp", "...."]
then this will inherently override the CMD
command described by the wnameless/oracle-xe-11g
's docker file.
So here are the steps to be done to achieve it
Step 1: copy the CMD's executed from the parent image (from the Dockerfile)
In my case that would be
/usr/sbin/startup.sh
Step 2: append your own CMD to the above CMD using && operation.
here it would be
bin/bash -c "/u01/app/oracle/product/11.2.0/xe/bin/impdp system/oracle NOLOGFILE=Y
Note that you need to include the entire path of the impdp and the whole operation inside blockquotes
Step 3: If the parent Dockerfile contains a background running process make sure that it goes in the last
Here it would be
/usr/sbin/sshd -D
The final output should be something like this
CMD /usr/sbin/startup.sh
&& bin/bash -c "/u01/app/oracle/product/11.2.0/xe/bin/impdp
system/oracle NOLOGFILE=Y ..."
&& /usr/sbin/sshd -D
That's it. This should work
Other things to keep in mind especially when using the above oracle dockerfile is you need to set the ENV for oracle_home and also export it to the bash.bashrc as this is not done by default.
# Add env variables for oracle_home and related
ENV ORACLE_HOME=/u01/app/oracle/product/11.2.0/xe \
ORACLE_SID=XE
#Export oracle_home and related
RUN echo 'export ORACLE_HOME=/u01/app/oracle/product/11.2.0/xe' >> etc/bash.bashrc
RUN echo 'export PATH=$ORACLE_HOME/bin:$PATH' >> /etc/bash.bashrc
RUN echo 'export ORACLE_SID=XE' >> /etc/bash.bashrc
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