I've been trying differnt ways of approaching this, but I'm not having to much luck.
Basically this query returns all the directories an employee is built into. I need to add a field to the select of this query that lists how many other users with 'admin' access (u.access_level) are built into the directory).
Table: Directories (has many users)
Table: Users (users of the directory with different access levels)
SELECT d.id, d.name, u.employee_number, u.access_level, u.id 'user_id',
(** count of all users of this directory where their u.access_level = 'admin) AS admins
FROM directories d JOIN users u ON d.id = u.directory_id
WHERE u.employee_number = '045283'
ORDER BY d.NAME
So, I need to return a recordset of all directories an employee is built into, including the total number of users that have 'admin' access to each directory. Basically I need a count for some later framework logic like 'if the employee is the last admin of this directory - don't allow them to delete themselves or change their access level - upgrade another user to admin level first).
It feels like I'm needing a sub-query, but that's a little beyond my SQL skills right now. Thanks for any help!
sum(if(u.access_level = 'admin',1,0)) as admins
edit. Please note that this condition can be rewritten even in this way
sum(u.access_level = 'admin')
because mysql simply returns 1 if condition is true or 0 if it's not.
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