I have a singleton class:
public class Singleton {
private static Singleton istance = null;
private Singleton() {}
public synchronized static Singleton getSingleton() {
if (istance == null)
istance = new Singleton();
return istance;
}
public void work(){
for(int i=0; i<10000; i++){
Log.d("-----------", ""+i);
}
}
}
And multiple Threads are calling the work() function:
public class Main {
public static void main(String[] args) {
new Thread (new Runnable(){
public void run(){
Singleton s = Singleton.getSingleton();
s.work();}
}).start();
System.out.println("main thread");
new Thread(new Runnable() {
public void run() {
Singleton s = Singleton.getSingleton();
s.work();
}
}).start();
}
}
I noticed the two Threads are running concurrently, as if two work functions were instantiated at the same time.
I want the last thread to be run in place of the previous thread, rather then concurrently. Is it possible in java to make the second call override the memory space of the first call?
When the Spring container creates a bean with the singleton scope, the bean is stored in the heap. This way, all the concurrent threads are able to point to the same bean instance.
The Singleton's purpose is to control object creation, limiting the number to one but allowing the flexibility to create more objects if the situation changes. Since there is only one Singleton instance, any instance fields of a Singleton will occur only once per class, just like static fields.
Is singleton thread safe? A singleton class itself is not thread safe. Multiple threads can access the singleton same time and create multiple objects, violating the singleton concept. The singleton may also return a reference to a partially initialized object.
Thread Safe Singleton: A thread safe singleton is created so that singleton property is maintained even in multithreaded environment. To make a singleton class thread safe, getInstance() method is made synchronized so that multiple threads can't access it simultaneously.
Your getSingleton()
method is attempting to lazily initializing the SINGLETON instance, but it has the following problems:
synchronized
volatile
so a race condition AMY cause two instances to be created.
The best and simplest was to safely lazily initialize a singleton without synchronization is as follows:
private static class Holder {
static Singleton instance = new Singleton();
}
public static Singleton getSingleton() { // Note: "synchronized" not needed
return Holder.instance;
}
This is thread safe because the contract of the java class loader is that all classes have their static initialization complete before they may be used. Also, the class loader does not load a class until it is referenced. If two thread call getSingleton()
simultaneously, the Holder
class will still only get loaded once, and thus new Singleton()
will only be executed once.
This is still lazy because the Holder
class is only referenced from getSingleton()
method, so the Holder
class will only be loaded when the first call to getSingleton()
is made.
Synchronization is not needed because this code relies on the class loader's internal synchronization, which is bullet proof.
This code pattern is the only way to fly with singletons. It is:
The other similar code pattern (equally safe and fast) is to use an enum
with a single instance, but I find this to be clumsy and the intention is less clear.
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