I have got a question, and it says "calculate the tight time complexity for the process of inserting n numbers into a binary search tree". It does not denote whether this is a balanced tree or not. So, what answer can be given to such a question? If this is a balanced tree, then height is logn, and inserting n numbers take O(nlogn) time. But this is unbalanced, it may take even O(n2) time in the worst case. What does it mean to find the tight time complexity of inserting n numbers to a bst? Am i missing something? Thanks
It could be O(n^2) even if the tree is balanced.
Suppose you're adding a sorted list of numbers, all larger than the largest number in the tree. In that case, all numbers will be added to the right child of the rightmost leaf in the tree, Hence O(n^2).
For example, suppose that you add the numbers [15..115] to the following tree:
The numbers will be added as a long chain, each node having a single right hand child. For the i-th element of the list, you'll have to traverse ~i nodes, which yields O(n^2).
In general, if you'd like to keep the insertion and retrieval at O(nlogn), you need to use Self Balancing trees.
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