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I have this task: sum all numbers in string and perform multiplication
input: "3 chairs, 2 tables, 2*3 forks" result: 11
I already have regular expression to do this:
eval(str.match(/(\d[\d\.\*]*)/g).join(' + '))
But I want to add option to ignore numbers inside brackets "()"
input: "2 chairs, 3 tables (1 broke)" result: 5
How to do it?
Regular expressions were always pain for me :(
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[] denotes a character class. () denotes a capturing group. [a-z0-9] -- One character that is in the range of a-z OR 0-9.
Regular expressions are patterns used to match character combinations in strings. In JavaScript, regular expressions are also objects. These patterns are used with the exec() and test() methods of RegExp , and with the match() , matchAll() , replace() , replaceAll() , search() , and split() methods of String .
In JavaScript, regular expressions are often used with the two string methods: search() and replace() . The search() method uses an expression to search for a match, and returns the position of the match. The replace() method returns a modified string where the pattern is replaced.
One simple way is to do a first pass and remove all parenthesized expressions.
str = str.replace(/\([^\)]*\)/g, "");
// now run your original algorithm to sum/multiply...
// ...
This is not super efficient but it does the job.
I should note that this does not handle nested parentheses, but it doesn't seem like that is required here.
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