I'm trying to compile and run following program without main()
function in C
. I have compiled my program using the following command.
gcc -nostartfiles nomain.c
And compiler gives warning
/usr/bin/ld: warning: cannot find entry symbol _start; defaulting to 0000000000400340
Ok, No problem. then, I have run executable file(a.out), both printf
statements print successfully, and then get segmentation fault.
So, my question is, Why segmentation fault after successfully execute print statements?
my code:
#include <stdio.h> void nomain() { printf("Hello World...\n"); printf("Successfully run without main...\n"); }
output:
Hello World... Successfully run without main... Segmentation fault (core dumped)
Note:
Here, -nostartfiles
gcc flag prevents the compiler from using standard startup files when linking
The answer is yes. We can write program, that has no main() function. In many places, we have seen that the main() is the entry point of a program execution. Just from the programmers perspective this is true.
yes it is possible to write a program without main().
How to write a running C code without main()? It's an entry point of every C/C++ program. All Predefined and User-defined Functions are called directly or indirectly through the main.
Let's have a look at the generated assembly of your program:
.LC0: .string "Hello World..." .LC1: .string "Successfully run without main..." nomain: push rbp mov rbp, rsp mov edi, OFFSET FLAT:.LC0 call puts mov edi, OFFSET FLAT:.LC1 call puts nop pop rbp ret
Note the ret
statement. Your program's entry point is determined to be nomain
, all is fine with that. But once the function returns, it attempts to jump into an address on the call stack... that isn't populated. That's an illegal access and a segmentation fault follows.
A quick solution would be to call exit()
at the end of your program (and assuming C11 we might as well mark the function as _Noreturn
):
#include <stdio.h> #include <stdlib.h> _Noreturn void nomain(void) { printf("Hello World...\n"); printf("Successfully run without main...\n"); exit(0); }
In fact, now your function behaves pretty much like a regular main
function, since after returning from main
, the exit
function is called with main
's return value.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With