I've prepared a simple variadic template test in Code::Blocks, but I'm getting an error:
No matching function for call to 'OutputSizes()'
Here's my source code:
#include <iostream>
#include <typeinfo>
using namespace std;
template <typename FirstDatatype, typename... DatatypeList>
void OutputSizes()
{
std::cout << typeid(FirstDatatype).name() << ": " << sizeof(FirstDatatype) << std::endl;
OutputSizes<DatatypeList...>();
}
int main()
{
OutputSizes<char, int, long int>();
return 0;
}
I'm using GNU GCC with -std=C++0x
. Using -std=gnu++0x
makes no difference.
Here's how you disambiguate the base case:
#include <iostream>
#include <typeinfo>
template <typename FirstDatatype>
void OutputSizes()
{
std::cout << typeid(FirstDatatype).name() << ": " << sizeof(FirstDatatype) << std::endl;
}
template <typename FirstDatatype, typename SecondDatatype, typename... DatatypeList>
void OutputSizes()
{
OutputSizes<FirstDatatype>()
OutputSizes<SecondDatatype, DatatypeList...>();
}
int main()
{
OutputSizes<char, int, long int>();
}
It's because you didn't provide a base case. You extracted the last data type of the variadic template parameter- then you tried to match an empty variadic parameter to a function taking a type and a variadic parameter. You need to provide a "base case" for when the variadic parameter is empty.
using namespace std;
template <typename FirstDatatype, typename... DatatypeList>
void OutputSizes()
{
std::cout << typeid(FirstDatatype).name() << ": " << sizeof(FirstDatatype) << std::endl;
OutputSizes<DatatypeList...>();
}
template<typename... DataTypeList>
void OutputSizes() // We're called when there's no template arguments
// left in the pack
{
}
int main()
{
OutputSizes<char, int, long int>();
return 0;
}
Edit: The many-zero overloads I have shown here actually only work when you take actual run-time arguments too based on the template types. If you only take template parameters directly, you have use two-one recursion like shown in Howard Hinnant's answer.
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