I have been going through several solutions, but I am not able to find a solution I need.
I have two numpy arrays. Let's take a small example here.
x = [1,2,3,4,5,6,7,8,9]
y = [3,4,5]
I want to compare x and y, and remove those values of x that are in y.
So I expect my final_x to be
final_x = [1,2,6,7,8,9]
I found out that np.in1d returns a boolean array the same length as x that is True where an element of x is in y and False otherwise. But how do I use it, if not any other method to get my final_x.??
If you really do have numpy arrays then you can use numpy.setdiff1d as below
import numpy as np
x = np.array([1,2,3,4,5,6,7,8,9])
y = np.array([3,4,5])
z = np.setdiff1d(x, y)
# array([1, 2, 6, 7, 8, 9])
Simply pass the negated version of boolean array returned by np.in1d to array x:
>>> x = np.array([1,2,3,4,5,6,7,8,9])
>>> y = [3,4,5]
>>> x[~np.in1d(x, y)]
array([1, 2, 6, 7, 8, 9])
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